Substituting Points into the Equation

Oct 13, 2025 by windailys.com 139 views

Introduction

Linear equations are a fundamental concept in mathematics, and they play a crucial role in various fields such as physics, engineering, and economics. A linear equation is an equation in which the highest power of the variable(s) is 1. In this article, we will explore three different problems related to linear equations and graphs.

Problem 3A: Points on the Line $y = 2x + 1$

The first problem asks us to determine which points are on the line $y = 2x + 1$ . To solve this problem, we need to substitute the coordinates of each point into the equation and check if it satisfies the equation.

Substituting Points into the Equation

Let's substitute the coordinates of each point into the equation $y = 2x + 1$ .

Point (1, -3)

Substituting $x = 1$ and $y = -3$ into the equation, we get:

$-3 = 2(1) + 1$

$-3 = 2 + 1$

$-3 = 3$

This is a false statement, so the point (1, -3) is not on the line.

Point (-2, -3)

Substituting $x = -2$ and $y = -3$ into the equation, we get:

$-3 = 2(-2) + 1$

$-3 = -4 + 1$

$-3 = -3$

This is a true statement, so the point (-2, -3) is on the line.

Point (0, 1)

Substituting $x = 0$ and $y = 1$ into the equation, we get:

$1 = 2(0) + 1$

$1 = 0 + 1$

$1 = 1$

This is a true statement, so the point (0, 1) is on the line.

Point (-3, -5)

Substituting $x = -3$ and $y = -5$ into the equation, we get:

$-5 = 2(-3) + 1$

$-5 = -6 + 1$

$-5 = -5$

This is a true statement, so the point (-3, -5) is on the line.

Conclusion

In conclusion, the points (-2, -3), (0, 1), and (-3, -5) are on the line $y = 2x + 1$ .

Problem 3B: Two Points from the Line $y = 2x$

The second problem asks us to find two points from the line $y = 2x$ . To solve this problem, we need to substitute two different values of $x$ into the equation and find the corresponding values of $y$ .

Substituting Values into the Equation

Let's substitute $x = 0$ and $x = 1$ into the equation $y = 2x$ .

Point (0, 0)

Substituting $x = 0$ into the equation, we get:

$y = 2(0)$

$y = 0$

So, the point (0, 0) is on the line.

Point (1, 2)

Substituting $x = 1$ into the equation, we get:

$y = 2(1)$

$y = 2$

So, the point (1, 2) is on the line.

Conclusion

In conclusion, the points (0, 0) and (1, 2) are on the line $y = 2x$ .

Problem 3C: $x$ -Intercept and $y$ -Intercept of $y = 3x - 6$

The third problem asks us to find the $x$ -intercept and $y$ -intercept of the line $y = 3x - 6$ . To solve this problem, we need to set $y = 0$ to find the $x$ -intercept and set $x = 0$ to find the $y$ -intercept.

Finding the $x$ -Intercept

To find the $x$ -intercept, we need to set $y = 0$ and solve for $x$ .

$0 = 3x - 6$

$6 = 3x$

$2 = x$

So, the $x$ -intercept is (2, 0).

Finding the $y$ -Intercept

To find the $y$ -intercept, we need to set $x = 0$ and solve for $y$ .

$y = 3(0) - 6$

$y = -6$

So, the $y$ -intercept is (0, -6).

Conclusion

In conclusion, the $x$ -intercept of the line $y = 3x - 6$ is (2, 0) and the $y$ -intercept is (0, -6).

Conclusion

Introduction

Linear equations and graphs are fundamental concepts in mathematics, and they play a crucial role in various fields such as physics, engineering, and economics. In this article, we will provide a Q&A guide to help you understand linear equations and graphs.

Q: What is a linear equation?

A: A linear equation is an equation in which the highest power of the variable(s) is 1. It can be written in the form of y = mx + b, where m is the slope and b is the y-intercept.

Q: What is the slope of a linear equation?

A: The slope of a linear equation is the ratio of the change in y to the change in x. It can be calculated using the formula m = (y2 - y1) / (x2 - x1).

Q: What is the y-intercept of a linear equation?

A: The y-intercept of a linear equation is the point where the line intersects the y-axis. It can be calculated using the formula b = y when x = 0.

Q: How do I graph a linear equation?

A: To graph a linear equation, you can use the slope-intercept form (y = mx + b) or the point-slope form (y - y1 = m(x - x1)). You can also use a graphing calculator or a computer program to graph the equation.

Q: What is the x-intercept of a linear equation?

A: The x-intercept of a linear equation is the point where the line intersects the x-axis. It can be calculated using the formula x = -b / m.

Q: How do I find the equation of a line given two points?

A: To find the equation of a line given two points, you can use the point-slope form (y - y1 = m(x - x1)) and then simplify the equation to the slope-intercept form (y = mx + b).

Q: What is the difference between a linear equation and a quadratic equation?

A: A linear equation is an equation in which the highest power of the variable(s) is 1, while a quadratic equation is an equation in which the highest power of the variable(s) is 2.

Q: How do I solve a system of linear equations?

A: To solve a system of linear equations, you can use the substitution method or the elimination method. You can also use a graphing calculator or a computer program to solve the system.

Q: What is the significance of linear equations in real-life applications?

A: Linear equations have numerous applications in various fields such as physics, engineering, economics, and computer science. They are used to model real-world problems, such as the motion of objects, the flow of fluids, and the growth of populations.

Conclusion

In conclusion, linear equations and graphs are fundamental concepts in mathematics, and they have numerous applications in various fields. This Q&A guide provides a comprehensive overview of linear equations and graphs, and it is designed to help you understand the concepts and solve problems related to linear equations and graphs.

Additional Resources

Khan Academy: Linear Equations and Graphs
Mathway: Linear Equations and Graphs
Wolfram Alpha: Linear Equations and Graphs

Practice Problems

Find the equation of the line that passes through the points (2, 3) and (4, 5).
Find the x-intercept and y-intercept of the line y = 2x - 3.
Solve the system of linear equations:
- 2x + 3y = 7
- x - 2y = -3

Answer Key

The equation of the line is y = 2x - 1.
The x-intercept is (3.5, 0) and the y-intercept is (0, -3).
The solution to the system of linear equations is x = 1 and y = 2.