Finding the Slope of the Line Segment

Oct 13, 2025 by windailys.com 130 views

Introduction

In geometry, a straight line segment is a part of a line that is bounded by two distinct points. The normal to a straight line segment is a line that is perpendicular to the segment at a given point. In this article, we will discuss how to find the equation of the normal to a straight line segment given its endpoints.

Understanding the Problem

We are given two points, A(6,8) and B(-9,-17), which are the endpoints of a straight line segment AB. Our goal is to find the equation of the normal to this line segment.

Finding the Slope of the Line Segment

To find the equation of the normal to the line segment, we first need to find the slope of the line segment. The slope of a line is a measure of how steep it is. It is calculated as the ratio of the vertical change (rise) to the horizontal change (run) between two points on the line.

The slope of the line segment AB can be found using the formula:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) and (x2, y2) are the coordinates of the two points.

Plugging in the values of the given points, we get:

m = (-17 - 8) / (-9 - 6) m = -25 / -15 m = 5/3

Finding the Slope of the Normal

The slope of the normal to a line is the negative reciprocal of the slope of the line. This means that if the slope of the line is m, the slope of the normal is -1/m.

In this case, the slope of the line segment AB is 5/3, so the slope of the normal is:

m_normal = -1 / (5/3) m_normal = -3 / 5

Finding the Equation of the Normal

Now that we have the slope of the normal, we can find its equation. The equation of a line in slope-intercept form is given by:

y = mx + b

where m is the slope and b is the y-intercept.

We can use the point-slope form of a line to find the equation of the normal. The point-slope form is given by:

y - y1 = m(x - x1)

where (x1, y1) is a point on the line and m is the slope.

We can use the point A(6,8) as the point on the line. Plugging in the values, we get:

y - 8 = (-3/5)(x - 6)

Simplifying the Equation

To simplify the equation, we can multiply both sides by 5 to eliminate the fraction:

5(y - 8) = -3(x - 6)

Expanding the equation, we get:

5y - 40 = -3x + 18

Rearranging the terms, we get:

5y = -3x + 58

Dividing both sides by 5, we get:

y = (-3/5)x + 58/5

Conclusion

In this article, we discussed how to find the equation of the normal to a straight line segment given its endpoints. We found the slope of the line segment, the slope of the normal, and the equation of the normal using the point-slope form. The final equation of the normal is:

y = (-3/5)x + 58/5

This equation represents the normal to the line segment AB.

Final Answer

The final answer is y = (-3/5)x + 58/5.

Introduction

In our previous article, we discussed how to find the equation of the normal to a straight line segment given its endpoints. In this article, we will answer some frequently asked questions related to this topic.

Q: What is the normal to a straight line segment?

A: The normal to a straight line segment is a line that is perpendicular to the segment at a given point.

Q: How do I find the slope of the line segment?

A: To find the slope of the line segment, you can use the formula:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) and (x2, y2) are the coordinates of the two points.

Q: What is the slope of the normal to a line?

A: The slope of the normal to a line is the negative reciprocal of the slope of the line. This means that if the slope of the line is m, the slope of the normal is -1/m.

Q: How do I find the equation of the normal to a line segment?

A: To find the equation of the normal to a line segment, you can use the point-slope form of a line:

y - y1 = m(x - x1)

where (x1, y1) is a point on the line and m is the slope.

Q: Can I use the slope-intercept form to find the equation of the normal?

A: Yes, you can use the slope-intercept form to find the equation of the normal. The slope-intercept form is given by:

y = mx + b

where m is the slope and b is the y-intercept.

Q: How do I simplify the equation of the normal?

A: To simplify the equation of the normal, you can multiply both sides by a common factor to eliminate any fractions. You can also rearrange the terms to get the equation in a more convenient form.

Q: What is the final equation of the normal to the line segment AB?

A: The final equation of the normal to the line segment AB is:

y = (-3/5)x + 58/5

Q: Can I use this equation to find the normal to any line segment?

A: Yes, you can use this equation to find the normal to any line segment, as long as you know the coordinates of the two endpoints.

Q: What if the line segment is vertical?

A: If the line segment is vertical, the slope of the line segment is undefined. In this case, the slope of the normal is also undefined, and the equation of the normal is a vertical line.

Q: What if the line segment is horizontal?

A: If the line segment is horizontal, the slope of the line segment is 0. In this case, the slope of the normal is undefined, and the equation of the normal is a horizontal line.

Conclusion

In this article, we answered some frequently asked questions related to finding the equation of the normal to a straight line segment. We hope that this article has been helpful in clarifying any doubts you may have had.

Final Answer

The final answer is that the equation of the normal to a line segment can be found using the point-slope form or the slope-intercept form, and the slope of the normal is the negative reciprocal of the slope of the line segment.