Calculating the Greatest Distance

Oct 13, 2025 by windailys.com 17 views

The equation (x+10)^2+(y-8)2=16 $}$ represents a circle with a center at ${(-10, 8)$ and a radius of 4 units. This equation is derived from the standard form of a circle, which is $(x - h)^{2} + (y - k)^{2} = r^{2}$ , where ${(h, k)$ is the center of the circle and ${r}$ is the radius.

Visualizing the Circle

To better understand the motion detector equation, let's visualize the circle it represents. The center of the circle is located at ${(-10, 8)}$ , which means that the circle is centered 10 units to the left of the origin and 8 units above the x-axis. The radius of the circle is 4 units, which means that the distance from the center of the circle to any point on the circle is 4 units.

Calculating the Greatest Distance

The greatest distance a person can be from the center of the circle and still be within the motion detector's boundary is equal to the radius of the circle. This is because the radius of the circle represents the maximum distance from the center of the circle to any point on the circle.

Finding the Greatest Distance

To find the greatest distance a person can be from the center of the circle, we need to calculate the radius of the circle. The radius of the circle is given by the square root of the constant term on the right-hand side of the equation, which is ${\sqrt{16} = 4}$ .

Conclusion

In conclusion, the greatest distance a person can be from the center of the circle and still be within the motion detector's boundary is equal to the radius of the circle, which is 4 units. This means that a person can be up to 4 units away from the center of the circle and still be detected by the motion detector.

Calculating the Greatest Distance in Feet

Since the radius of the circle is 4 units, the greatest distance a person can be from the center of the circle and still be within the motion detector's boundary is equal to the radius of the circle in feet. To convert the radius from units to feet, we need to know the conversion factor between units and feet. Assuming that 1 unit is equal to 1 foot, the radius of the circle is equal to 4 feet.

The Final Answer

Therefore, the greatest distance a person can be from the center of the circle and still be within the motion detector's boundary is 4 feet.

Key Takeaways

The equation ${$ (x+10)^2+(y-8)2=16$}$ represents a circle with a center at ${(-10, 8)}$ and a radius of 4 units.
The greatest distance a person can be from the center of the circle and still be within the motion detector's boundary is equal to the radius of the circle.
The radius of the circle is 4 units, which is equal to 4 feet.

Additional Resources

For more information on the equation of a circle, see the Wikipedia article on the equation of a circle.
For more information on the motion detector equation, see the Wikipedia article on motion detectors.

Practice Problems

What is the center of the circle represented by the equation ${$ (x-3)^2+(y+2)2=9$}$?
What is the radius of the circle represented by the equation ${$ (x+2)^2+(y-5)2=25$}$?
What is the greatest distance a person can be from the center of the circle represented by the equation ${$ (x-1)^2+(y+3)2=16$}$?

Solutions to Practice Problems

The center of the circle represented by the equation ${$ (x-3)^2+(y+2)2=9$}$ is ${(3, -2)}$ .
The radius of the circle represented by the equation ${$ (x+2)^2+(y-5)2=25$}$ is ${\sqrt{25} = 5}$ .
The greatest distance a person can be from the center of the circle represented by the equation ${$ (x-1)^2+(y+3)2=16$}$ is equal to the radius of the circle, which is ${\sqrt{16} = 4}$ .
Q&A: Circles and Motion Detectors =====================================

Q: What is the equation of a circle?

A: The equation of a circle is given by ${(x-h)^2 + (y-k)^2 = r^2}$ , where ${(h, k)}$ is the center of the circle and ${r}$ is the radius.

Q: What is the center of the circle represented by the equation ${$ (x+10)^2+(y-8)2=16$}$?

A: The center of the circle represented by the equation ${$ (x+10)^2+(y-8)2=16$}$ is ${(-10, 8)}$ .

Q: What is the radius of the circle represented by the equation ${$ (x+10)^2+(y-8)2=16$}$?

A: The radius of the circle represented by the equation ${$ (x+10)^2+(y-8)2=16$}$ is ${\sqrt{16} = 4}$ .

Q: What is the greatest distance a person can be from the center of the circle represented by the equation ${$ (x+10)^2+(y-8)2=16$}$?

A: The greatest distance a person can be from the center of the circle represented by the equation ${$ (x+10)^2+(y-8)2=16$}$ is equal to the radius of the circle, which is 4 units.

Q: How do I convert the radius from units to feet?

A: To convert the radius from units to feet, you need to know the conversion factor between units and feet. Assuming that 1 unit is equal to 1 foot, the radius of the circle is equal to 4 feet.

Q: What is the greatest distance a person can be from the center of the circle and still be within the motion detector's boundary?

A: The greatest distance a person can be from the center of the circle and still be within the motion detector's boundary is equal to the radius of the circle, which is 4 feet.

Q: How do I find the center and radius of a circle given its equation?

A: To find the center and radius of a circle given its equation, you need to rewrite the equation in the standard form ${(x-h)^2 + (y-k)^2 = r^2}$ . The center of the circle is ${(h, k)}$ and the radius is ${r}$ .

Q: What is the equation of a circle with a center at ${(3, 4)}$ and a radius of 2 units?

A: The equation of a circle with a center at ${(3, 4)}$ and a radius of 2 units is ${(x-3)^2 + (y-4)^2 = 4}$ .

Q: What is the equation of a circle with a center at ${(-2, 1)}$ and a radius of 3 units?

A: The equation of a circle with a center at ${(-2, 1)}$ and a radius of 3 units is ${(x+2)^2 + (y-1)^2 = 9}$ .

Q: How do I find the greatest distance a person can be from the center of a circle given its equation?

A: To find the greatest distance a person can be from the center of a circle given its equation, you need to find the radius of the circle. The radius of the circle is given by the square root of the constant term on the right-hand side of the equation.

Additional Resources

For more information on the equation of a circle, see the Wikipedia article on the equation of a circle.
For more information on motion detectors, see the Wikipedia article on motion detectors.

Practice Problems

What is the center of the circle represented by the equation ${$ (x-5)^2+(y+3)2=9$}$?
What is the radius of the circle represented by the equation ${$ (x+1)^2+(y-2)2=16$}$?
What is the greatest distance a person can be from the center of the circle represented by the equation ${$ (x-2)^2+(y+1)2=25$}$?

Solutions to Practice Problems

The center of the circle represented by the equation ${$ (x-5)^2+(y+3)2=9$}$ is ${(5, -3)}$ .
The radius of the circle represented by the equation ${$ (x+1)^2+(y-2)2=16$}$ is ${\sqrt{16} = 4}$ .
The greatest distance a person can be from the center of the circle represented by the equation ${$ (x-2)^2+(y+1)2=25$}$ is equal to the radius of the circle, which is ${\sqrt{25} = 5}$ .